What is the mass, in grams, of MgCl2 is consumed when 255g Mg(OH)2 is produced? MgCl2 + 2 LiOH → Mg(OH)2 + 2 LiCl

416 g MgCl₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Balanced]   MgCl₂ + 2LiOH → Mg(OH)₂ + 2LiCl

[Given]   255 g Mg(OH)₂

[Solve]   x g MgCl₂

Step 2: Identify Conversions

[RxN] 1 mol MgCl₂ → 1 mol Mg(OH)₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Mg(OH)₂- 24.31 + 2(16.00) + 2(1.01) = 58.33 g/mol

Molar Mass of MgCl₂ - 24.31 + 2(35.45) = 95.21 g/mol

Step 3: Stoichiometry

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

416.227 g MgCl₂ ≈ 416 g MgCl₂

chemistry sucks a**

explanation:

a is the answer to this question

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