2 Na + Cl2 --> 2 NaCl If 15 mol Na reacts with 15 mol Cl2, what is the theoretical yield of NaCl that could be
formed?

Theoretical yield of NaCl = 877.5 g or 15 moles

Explanation:

Given data:

Number of moles of Na = 15 mol

Number of moles of Cl₂ = 15 mol

Theoretical yield of NaCl = ?

Solution:

Chemical equation:

2Na + Cl₂      →     2NaCl

Now we will compare the moles of Na and Cl₂ with NaCl.

                Cl₂       :        NaCl

                 1          :          2

               15          :         2/1×15 = 30 mol

                Na       :        NaCl

                 2          :          2

               15          :          15

Less number of NaCl are produced by Na it will act as limiting reactant.

Theoretical yield:

Mass = number of moles × molar mass

Mass = 15 mol × 58.5 g/mol

Mass = 877.5 g

the dependant variable is spilled water

the independent is the heat