2NaClO3 (s) → 2NaCl (s) + 3O2 (g) 12.00 moles of NaClO3 will produce how many grams of O2?

MM NaClO3: 106.44 g/mol

MM NaCl: 58.44 g/mol

MM O2: 32.00 g/mol

Question 2 options:

a)

256 g of O2

b)

384 g of O2

c)

576 g of O2

d)

288 g of O2

Mass O2 produced : 576 g

Given

Reaction

2NaClO3 (s) → 2NaCl (s) + 3O2 (g)

Required

mass of O2

Solution

From the equation, mol ratio of NaClO3 : O2 = 2 : 3, so mol O2 :

= 3/2 x mol NaClO3

= 3/2 x 12 moles

= 18 moles

Mass O2 :

= mol x MW

= 18 x 32 g/mol

= 576 g

alienation, transformation, consumption, and the relativity of truth.

you can choose any one of these, they are all important themes.

these themes reflect the distinct sensibilities of both the modernist and postmodern aesthetic movements. (from google, you should paraphrase)

hope this !

- melanie

2b2t

explanation:

2b2t