How many moles of nitrogen (N2) are needed to produce 9.60x10^24 molecules of nitrogen dioxide (NO2)? *

The number of moles of Nitrogen : == 7.975

Given

9.60x10²⁴ molecules  of nitrogen dioxide (NO2)

Required

The number of moles

Solution

Reaction

N2 + 2O2 → 2NO2

moles of NO2 :

= 9.6 x 10²⁴ : 6.02 x 10²³

= 15.95

From the equation, mol N2 :

= 1/2 x mol NO2

= 1/2 x 15.95

= 7.975

The number of molecules :

= 8 x 6.02 x 10²³

= 4.816 x 10²⁴

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.