Based on the equation below, how many grams of nitrogen gas will be produced from the decomposition of one mole of sodium aside? Use a molar mass of 28.0 grams for nitrogen gas.

Mass of Nitrogen= 42 grams

Given

one mole of Sodium azide

Required

mass of Nitrogen

Solution

Reaction

The decomposition of one mol of sodium azide :

2 N a N 3 ( s ) → 2Na ( s ) + 3 N2 ( g )

From the equation, the mol ratio of N a N 3 ( s ) :  N2 ( g ) = 2 : 3, so mol N2 :

= 3/2 x mol N a N 3

= 3/2 x 1

= 1.5 moles

Mass of Nitrogen

= mol x molar mass

= 1.5 x 28 g/mol

= 42 grams

i just learnt this recently but i need to look through my notes again