A chemical process used to produce ethanol as a fuel additive was expected to produce 5,000 kilograms of ethanol based on the amounts of starting materials used, but only 4,760 kilograms were produced. What was the percent yield for ethanol in this process? A)1.09 percent B)4.80 percent C)95.2 percent D)105 percent

The percent yield for ethanol in this process is 95.2%

Explanation:

Yield is the ratio between the amount of product actually obtained in the reaction and the maximum amount of product that could have been obtained if the reagents had been completely consumed.

The theoretical yield is the yield is the maximum you can get in a reaction.

On the other hand, the actual performance shows what you really get in experimentation. It is generally less than the theoretical yield.

So, the percentage return is the actual return times the theoretical return multiplied by 100.

So, in this case the percentage yield will be calculated as:

percent yield=  95.2%

The percent yield for ethanol in this process is 95.2%

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.