a sample of nitrogen gas occupies 1.55l at 27.0c and 1.00 atm what will the volume be at -100.0c and the same pressure

V₂=0.894 L

Given

V₁=1.55 L

T₁=27 + 273 = 300 K

P₁=1 atm

T₂=-100+273 = 173 K

Required

The final volume(V₂)

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

Input the value :

V₂=V₁T₂/T₁

V₂=1.55 x 173/300

V₂=0.894 L

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

the answer is c

tell me if wrong