Chemistry, 07.02.2021 23:00 MNBASKETBALL838
Pb(NO3)2 (aq) +
Nal (aq)
Pb12 (s) +
NaNO3(aq)
a)If I start with 25.0 grams of lead (II) nitrate and 15.0
grams of sodium iodide, how many grams of sodium
nitrate can be formed?
b)What is the limiting reagent in the reaction described in
problem a?
c) How many grams of lead(II) iodide is formed?
d)How much of the nonlimiting reagent will be left over
from the reaction in the problem a?
Answers: 3
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Pb(NO3)2 (aq) +
Nal (aq)
Pb12 (s) +
NaNO3(aq)
a)If I start with 25.0 grams of lea...
Pb12 (s) +
NaNO3(aq)
a)If I start with 25.0 grams of lea...
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