Consider the unbalanced equation for the oxidation of butene. c4h8 6o2 mc022-co2 h2o for each molecule of c4h8 that reacts, how many molecules of carbon dioxide and water are produced? two carbon dioxide molecules and two water molecules four carbon dioxide molecules and four water molecules two carbon dioxide molecules and four water molecules four carbon dioxide molecules and two water molecules

Answer is: four carbon dioxide molecules and four water molecules.

Balanced chemical reaction: C₄H₈ + 6O₂ → 4CO₂ + 4H₂O.

There are four carbon dioxide molecules (CO₂) on the right side of chemical reaction, because there are four carbon atoms on the left side of balanced chemical reaction.

There are four water molecules (H₂O) on the right side of chemical reaction, because there are eight hydrogen atoms on the left side of balanced chemical reaction.

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