A 1.00 L volume of dry air is sealed inside of a round flask and brought to a temperature of 50.0°C in a hot water bath. If the pressure gauge reads 3.60 atm, how many moles of gas are in the sample of

air?

0.136mol

Explanation:

Using the general gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (Litres)

n = number of moles (mol)

R = gas constant (0.0821 Latm/mol K)

T = temperature (K)

K = °C + 273

K = 50°C + 273

K = 323K

According to this question, P = 3.6atm, T = 323K, V = 1.00L, R = 0.0821 Latm/mol K, n = ?

3.6 × 1 = n × 0.0821 × 323

3.6 = 26.52n

n = 3.6/25.52

n = 0.1357

n = 0.136mol

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alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.