What is the correct hybridization for a ion of IF6 that has a charge of (1-)​

6 F atoms at 6 corners

Explanation:

The shape of IF6 (-1) is trigonally distorted octahedron. The central iodine atom has 7 valence electrons. It gains one electron from negative charge. Out of 8 electrons, 6 are imvolved in formation of 6 I - F bonds and one lone pair of electrons is present. 6F atoms are present at 6corners of distorted octahedron. The lone pair of electrons distorts the octahedral shape due to electron repulsion.

not clear

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6