What is the molarity of the solution of Sodium hydroxide, if 35 ml of 0.1 M HCl is used in the titration of 25 ml of the barium hydroxide solution

The molarity of is 0.07 M

Explanation:

According to the neutralization law,

where,

= basicity = 1

= molarity of solution = 0.1 M

= volume of   solution = 35 ml

= acidity of = 2

= molarity of solution = ?

= volume of   solution = 25 ml

Putting in the values we get:

Therefore, molarity of is 0.07 M

increased stability in the completion of fluorine's outer shell.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2