What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to raise the temperature from 22ᵒC to 33.6ᵒC?

≈ 395,8 J/(kg * °C)

Explanation:

m = 44 g = 0,044 kg

= 22 °C

= 33,6 °C

Q = 202 J

The formula is: Q = c * m * ()

c =

Calculating:

c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.