(e) Calculate the mass of one atom of sodium.
Use the equation:
relative atomic mass
mass of one atom of sodium =
Avogadro constant
Avogadro constant = 6.02 x 1023
Give your answer to 2 significant figures

3.82 × 10 ^-23 g

Explanation:

6.02 x 10^23atoms = 1 mole of sodium

1 atom = 1/(6.02 x 10^23) mole

mass = mole × molar mass

= 1/(6.02 x 10^23) × 23

= 3.82 × 10 ^-23 g

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

if you're asking what comes out, it's steam.