Answer the following questions using the results of the following Unknown Solution Analysis: Flame test: red flame Solutions reactions:
ammonium carbonate - white precipitate (ppt.) ammonium phosphate - white ppt. ammonium sulfate - white ppt. Halide test: purple hexane layer
a) What is the complete chemical name of the unknown ionic compound? (0.5 pt).
b) What is its correct chemical formula? (0.5 pt.)

(a). strontium iodide.

(b). SrI2.

Explanation:

This question wants to test our knowledge on qualitative part of chemistry practical.

The first part is flame test which is a physical test. The flame test that was done on the com gave red flame.

Deduction: This confirms the presence of Strontium and Calcium.

The next thing is the chemical tests.

(1). Unknown + ammonium carbonate: gives white precipitate (ppt.).

Deduction: presence of Calcium and Strontium ions

(2). Unknown + Ammonium phosphate - white ppt.

Deduction: presence of Calcium and Strontium ions.

(3). Unknown sample + ammonium sulfate - white ppt.

Deduction: presence of Strontium ion confirmed.

(3). Halide test: purple hexane layer.

Deduction: shows the presence of Iodine.

Therefore, the final conclusion can be made as;

(a). The name of the chemical compound is strontium iodide.

(b). The chemical formula for the compound is SrI2.

dynamic equilibrium is the answer.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally