#1: the element that loses electrons in a chemical reaction is said to have been which of the following?

a. reduced

b. oxidized

c. combusted

d. rusted

**idk, is it reduced or oxidized? ?

which type of reaction occurs if one element gains electrons and another loses electrons?

a. combustion

b. synthesis

c. oxidation-reduction

d. double-displacement

**my c

#3: what is the oxidation number for phosphorus in h4p2o7?

a. +5

b. +3

c. +1

d. - 1

**my a. +5

#4: what is the oxidation number for phosphorus in na2hpo3?

a. +5

b. +3

c. +1

d. - 1

**my answer; b. +3

is that right? ?

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years