This compound is treated with two different oxidizing reagents: either H2CrO4 and H2SO4, or with PCC. Draw the major organic product for each of the oxidation reactions. Do not draw inorganic by-products.

See explanation and image attached

Explanation:

We were told that one of two different oxidizing agents were used H2CrO4 and H2SO4 or PCC/CH2Cl2.

Now, we must know that when we use H2CrO4 and H2SO4, primary alcohols are converted to aldehydes and then to carboxylic acids while secondary alcohols are converted to ketones.

When we use PCC/CH2Cl2 primary alcohols are converted to aldehydes and does not move further to convert to carboxylic acids while secondary alcohols are converted to ketones.

Recall that tertiary alcohols are not oxidized at all.

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explanation:

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.