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Iron combines with 5 g of Copper (1) Nitrate to form 6.01 g of Iron (1) Nitrate and 0.4 g of copper metal. How much Iron was required to complete this reaction?
Answers: 1
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Iron combines with 5 g of Copper (1) Nitrate to form 6.01 g of Iron (1) Nitrate and 0.4 g of copper...
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