What is the volume, in liters, of a 0.2 M solution containing 8.5 grams of AgNO3?

The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L

Explanation:

 Molarity (M) is a common way of expressing the concentration of solutions. It is defined as the number of moles of solute per volume of solution. The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution.

Molarity is expressed in units .

Being the molar mass of AgNO3 169.87 g / mol, then you can apply the following rule of three: if 169.87 grams are present in 1 mole of the compound, 8.5 grams will be present in how many moles?

amount of moles= 0.05

So, being the molarity equal to 0.2 M, replacing in the definition of molarity:

and solving you get:

volume=0.25 L

The volume of a 0.2 M solution containing 8.5 grams of AgNO₃ is 0.25 L

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.