EX/Cupper(I)Iodide *What was happen if excess amount of potassium iodide and sodium thiosulfate added?

*How can increase rate of the reaction?

*What is role of the product washing by water, ethanol and ether?​

Explanation:

Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.

2CuSO

4

+4KI→Cu

2

I

2

↓+I

2

+2K

2

SO

4

Thus, CuI

2

is not formed in this reaction.

Hence, the option B is incorrect and option A is correct.

The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.

2Na

2

S

2

O

3

+I

2

→Na

2

S

4

O

6

+2NaI

Iodine is reduced and sodium thiosulphate is oxidized.

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

explanation: