Find the molecules in 75.0 liters of F2 at STP

20.16 × 10^(23) molecules

Explanation:

We know that At STP, 22.4 L of any substance = 6.02 × 10^(23) molecules

Thus;

75 L of F2 at STP will give;

(75 × 6.02 × 10^(23))/22.4 = 20.16 × 10^(23) molecules

Number of molecules in 75.0 liters of F2 at STP = 20.16 × 10^(23) molecules

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

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