Chemistry, 15.02.2021 14:00 stormymoreland375

read carefully and do this questions all part all questions if someone do this questions I will make you and give you thanks.

read carefully and do this questions all part all questions if someone do this questions I will mak

Answers: 1

Show answers

Answers

Answer from: skaterwolf1317

Question 1.

a. the product of the reaction above that contains calcium is calcium chloride, CaCl₂.

b. hydrochloric acid, HCl is the reactant that contains hydrogen

c. the product water, H₂O contains hydrogen

d. the reactant, calcium carbonate, CaCO₃ contains carbon

e. The product carbon (iv) oxide contains carbon

Question 2:

a. atoms of hydrogen and oxygen bonded together as a single compound known as water molecules are present at the start of the reaction

b. two molecules of water are present at the start of the reaction

c. two individual atoms of hydrogen and oxygen existing as molecules are present at the end of the reaction.

d. at the end of the reaction, two molecules of hydrogen and one molecule of oxygen are present.

Question 3:

a. total mass of products = 187 g

b. 10 g of magnesium will be found in the magnesium sulfate

Explanation:

Question 1: The equation of the reaction between calcium carbonate and hydrochloric acid is given as follows: + 2HCl ---> CaCl₂ + H₂O + CO₂

a. the product of the reaction above that contains calcium is calcium chloride, CaCl₂.

b. the reactant, hydrochloric acid, HCl contains hydrogen

c. the product water, H₂O contains hydrogen

d. the reactant, calcium carbonate, CaCO₃ contains carbon

e. The product carbon (iv) oxide contains carbon

Question 2: the equation of the reaction in which water is broken down to hydrogen and oxygen is as follows: 2H₂O > 2H₂ + O₂

a. atoms of hydrogen and oxygen bonded together as a single compound known as water molecules are present at the start of the reaction

b. two molecules of water are present at the start of the reaction

c. two individual atoms of hydrogen and oxygen existing as molecules are present at the end of the reaction.

d. at the end of the reaction, two molecules of hydrogen and one molecule of oxygen are present.

Question 3: The equation of the reaction between magnesium and sulfuric acid is given as follows: Mg + H₂SO₄ ---> MgSO₄ + H₂

molar mass of Mg = 24.0 g; molar mass of H₂SO₄ = 98.0 g

a. According to the law of conservation of mass, when 37.0 g of magnesium is reacted with 150 g of H₂SO₄, the total mass of products of the reaction = total mass of reactants = 150 + 37 = 187 g

b. if Chinua starts with 10 g of magnesium, the same 10 g of magnesium will be found in the magnesium sulfate

Answer from: Quest

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

Another question on Chemistry

Chemistry, 22.06.2019 04:30

Suppose that during that icy hot lab 65,000 j of energy were transferred to 450 g of water at 20°c what would have have been the final temperature of the water

Answers: 2

Answer

Chemistry, 22.06.2019 05:30

What type of reaction is shown below? check all that apply. 2h2o2 → 2h2o + o2 synthesis decomposition combustion

Answers: 1

Answer

Chemistry, 22.06.2019 07:00

Achemist wants to extract copper metal from copper chloride solution. the chemist places 0.50 grams of aluminum foil in a solution containing 0.75 grams of copper (ii) chloride. a single replacement reaction takes place. (ii) chloride. a single replacement reaction takes place. which statement explains the maximum amount of copper that the chemist can extract using this reaction? a) approximately 0.36 grams, because copper (ii) chloride acts as a limiting reactant b) approximately 1.8 grams, because copper (ii) chloride acts as a limiting reactant c) approximately 0.36 grams, because aluminum acts as a limiting reactant d) approximately 1.8 grams, because aluminum acts as a limiting reactant

Answers: 3

Answer

Chemistry, 22.06.2019 09:30

Why do cells appear different in distilled water than they do in 10% salt water?

Answers: 2

Answer

You know the right answer?

read carefully and do this questions all part all questions if someone do this questions I will make...

Questions