calculate the volume (in mL) of 0.100 M CaCl2 needed to produce 1.00 g of CaCO3 (s). There is an excess of Na2CO3. Volume of calcium chloride in mL

100. mL

Explanation:

Step 1: Write the balanced equation for the double displacement reaction

CaCl₂ + Na₂CO₃ ⇒ 2 NaCl + CaCO₃

Step 2: Calculate the moles corresponding to 1.00 g of CaCO₃

The molar mass of CaCO₃ is 100.09 g/mol.

1.00 g × 1 mol/100.09 g = 0.0100 mol

Step 3: Calculate the moles of CaCl₂ required to produce 0.0100 moles of CaCO₃

The molar ratio of CaCl₂ to CaCO₃ is 1:1. The moles of CaCl₂ required are 1/1 × 0.0100 mol = 0.0100 mol.

Step 4: Calculate the volume of 0.100 M CaCl₂ that contains 0.0100 mol

0.0100 mol × 1 L/0.100 mol × 1000 mL/1 L = 100. mL

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

the answer is 0.8m.

by: nicholas