Given the following reaction: 2NO(g) + 2H2 (9) --> N2 (9) + 2H20 (9)
When the reaction occurs and the reactant NO decreases by a molar amount x, how much will the product N2 molar amount increase?
А. х
B. 2x
C. 3x
D. 0.5x

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the answer is the first option

explanation:

just googled it m8. not that hard

lol

the answer is minerals.