The specific heat of a metal is 3.76 cal/g°C. How much heat energy will it take to heat a 25.0 g cylinder of the metal from 21.5°C to 77.0°C?

The correct answer is "5217 Cal".

Explanation:

The given values are:

Specific heat,

c = 3.76 cal/g°C

Mass,

m = 25.0 g

Initial temperature,

T₁ = 21.5°C

Final temperature,

T₂ = 77.0°C

Now,

The heat energy will be:

⇒

On substituting the given values, we get

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⇒    

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