Please help 3. The combustion of glucose is represented by the following balanced equation: C6H12O6 + 602 - 6H20 + 6CO2. Which reactant is the limiting reagent if there is 1 gram of both C6H12O6 and O2? (Hint: Must convert to moles to determine this.)
O a C. H 20
O bO2
O c H₂O
Od CO₂

Explanation:

C₆H₁₂O₆       +      60₂     =     6H₂0     +     6CO₂.

1 mole              6 mole

molecular weight of C₆H₁₂O₆ = 180 g

molecular weight of oxygen = 32 g

1 gram of glucose = 1 / 180 = 5.55 x 10⁻³ moles

1 gram of oxygen = 1 / 32 = 31.25 x 10⁻³ moles

1 mole of glucose reacts with 6 moles of oxygen

5.55 x 10⁻³ moles of glucose will react with 6 x 5.55 x 10⁻³ moles of oxygen

= 33.30 x 10⁻³ moles of oxygen .

But oxygen available = 31.25 x 10⁻³ moles

So available oxygen is less than required .

Hence oxygen is the limiting reagent .

b ) is the right option .

d.) circle motion requires a force to give it a centripetal acceleration.

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.