You have 9.3 mL of a 0.031 M solution of NaOH. If you add this solution to 8.5 mL of a 0.012 M solution of crystal violet, what is the initial concentration of NaOH in the reaction mixture?

0.016M is the initial concentration of NaOH in the reaction mixture

Explanation:

The NaOH is diluted from 9.3mL to 9.3mL + 8.5mL = 17.8mL. That is a dilution of:

17.8mL / 9.3mL = 1.914 times

As the initial concentration of the NaOH solution is 0.031M and is diluted 1.914 times, the final concentration of the NaOH solution is:

0.031M / 1.914 =

0.016M is the initial concentration of NaOH in the reaction mixture

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