For the balanced equation 2C6H6OS+1102=12CO+6H2O+2SO3 how many moles of C6H6OS reacted if 0.474 moles of SO3 are produced?

0.474 moles of C₆H₆OS

Explanation:

Step 1: Write the balanced equation

2 C₆H₆OS + 11 O₂ ⇒ 12 CO + 6 H₂O + 2 SO₃

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of C₆H₆OS to SO₃ is 2:2.

Step 3: Calculate the moles of C₆H₆OS reacted if 0.474 moles of SO₃ are produced

We will use the previously established molar ratio.

0.474 mol SO₃ × 2 mol C₆H₆OS/2 mol SO₃ = 0.474 mol C₆H₆OS

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole