Lead will react with hydrochloric acid to produce lead (II) chloride and hydrogen. How many moles of hydrochloric acid are needed to completely react with 0.36 mol of lead?

0.72 moles of hydrochloric acid are needed to completely react with 0.36 mol of lead.

Explanation:

The balanced  reaction is:

Pb + 2 HCl → PbCl₂ + H₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagent participate:

You can apply the following rule of three: if by stoichiometry of the reaction 1 mole of Pb reacts with 2 moles of HCl, 0.36 moles of Pb will react with how many moles of HCl?

amount of moles of HCl= 0.72 moles

0.72 moles of hydrochloric acid are needed to completely react with 0.36 mol of lead.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

a. they are both space stations

happy to

pls mark as brainliest.