If 8.00 moles of NH₃ of and 10.00 moles of O₂ react in the following reaction, how many moles of which reactant will be left over? 4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g) A) 2.00 mol O₂
B) 2.00 mol NH₃
C) 8.00 mol NO
D) no moles will be left over of either reactant because both are limiting.

Option (D) no moles will be left over of either reactant because both are limiting

Explanation:

The balanced equation for the reaction is given below:

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)

From the balanced equation above,

4 moles of NH₃ reacted with 5 moles of O₂.

Next, we shall determine the excess reactant. This can be obtained as follow:

From the balanced equation above,

4 moles of NH₃ reacted with 5 moles of O₂.

Therefore, 8 moles of NH₃ will react with = (8 × 5)/4 = 10 moles of O₂.

From the calculations made above, we see clearly that 10 moles of O₂ reacted completely with 8 moles of NH₃. This implies that both reactant are limiting reactant and there is no excess reactant.

Thus, no reactant is left over.

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.