Problems 4-6 convert the measurements into moles. 4. 9.03 x1023 C atoms

5. 2.44x1023 H2O molecules

6. 6.02x1023 Li atoms

4. 1.5moles

5. 0.405moles

6. 1 mol

Explanation:

To find the number of moles in each susbtance in this question, we divide each number of atom/molecule measurement by Avagadro's number (6.02 × 10^23 atoms)

That is; nA = n × 6.02 × 10^23 atoms

n = nA ÷ 6.02 × 10^23 atoms

Where;

nA = number of atoms

n = number of moles

4.) n of Carbon = 9.03 x 10^23 ÷ 6.02 × 10^23

n = 1.5 × 10^ (23-23)

n = 1.5 × 10^0

n = 1.5 × 1

n = 1.5moles.

5.) n of H2O = 2.44 x 10^23 ÷ 6.02 × 10^23

n = 0.405 × 10^ (23-23)

n = 0.405 × 10^0

n = 0.405moles

6.) n of lithium = 6.02 x 10^23 Li atoms ÷ 6.02 × 10^23

n = 1 × 10^ (23-23)

n = 1 × 10^0

n = 1 mol

the answer is 303.15 or 303