Graphite has a specific heat of 0.709 J/gºC. If a 25 gram piece of graphite is cooled by 17°C, how much energy was lost by the graphite?

Explanation:

Since we are given the mass, specific heat, and change in temperature, we should use this formula for energy:

The mass of the graphite is 25 grams. Graphite's specific heat is 0.709 J/g °C. The change in temperature is 17 degrees Celsius.

Substitute the values into the formula.

Multiply the first two numbers. The grams will cancel.

Multiply again. This time the degrees Celsius cancel.

The graphite loses 301.325 Joules of energy.

the answer is d : ) have a good da

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.