Balance kclo3-kcl+02​

Explanation:

KClO

3

→KCl+3O

2

There are 6 O on the right and 3 on the left

so multiply the KClO

3

by 2

2KClO

3

→KCl+3O

2

now there are 6 O on both sides

Balance the K and Cl by multiplying KCl on the right by 2

2KClO

3

→2KCl+3O

2

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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