1. The equation for the reaction between zinc and aqueous copper(II) sulfate is shown. Zn + Cuso, → ZnSO, + Cu

Which statement is correct?

a. The oxidation state of the oxidising agent has changed from 0 to +2.

b. The oxidation state of the reducing agent has changed from 0 to +2.

c. The oxidation state of the reducing agent has changed from +2 to 0

d. This is not a redox reaction. The solution changes from colourless to blue.

2. Complete these half-equations. Balance the charges by adding electrons. State whether oxidation or reduction has taken place.

1. Pb4+ + 2e—>
2. Br1- —>+
3.O2 +—> O2-

3. When aqueous iron(III) chloride is added to aqueous potassium iodide occurs and iodine is formed.

Which statement is correct?

a. lodide ions are oxidised, they gain electrons in this reaction.

b. Neither iodide ions nor iron (III) chloride is oxidised in this reaction.

c. lodide ions are oxidised, they lose electrons in this reaction.

d. Iron (III) chloride is oxidised in this reaction.

a electronegativity decreases beacuse the size of nucleus is bigger.

you did not give any options thus this is the best answer i can give to you with this little information you have given

> they are both natural and not man made

> they can be tracked and predicted by the right tools

-love shrooms

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.