Based on the following equation, how many moles of hydrochloric acid (HCl)are needed to react with 0.44 moles of potassium permanganate (KMnO4)?
2KMnO4 + 8HCI - 3Cl2 + 2MnO2 + 4H2O + 2KCI

1.76 moles of HCl.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KMnO₄ + 8HCl —> 3Cl₂ + 2MnO₂ + 4H₂O + 2KCl

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Finally, we shall determine the number of mole of HCl needed to react with 0.44 moles of KMnO₄. This can be obtained as follow:

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Therefore, 0.44 moles of KMnO₄ will react with = (0.44 × 8)/2 = 1.76 moles of HCl.

Thus, 1.76 moles of HCl is needed for the reaction.

precipitation

explanation:

when it goes from cloud to rain/back to earth in the form of rain

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.