7. A 1.50 x 103 kg car accelerates uniformly from rest to 10.0 m/s in 3.00 s. a. What is the work done on the car in this time interval?

b. What is the power delivered by the engine in this time interval?

Work done = force*distance = mass*acceleration*distance

acceleration = 10/3 = 3.33 m/s^2

distance = ((0+10)/2)*3 = 15m

work done = 1500*3.33*15 = 74900 J

Power = workdone/time = 74900/3 = 25000 W

the answer is b. dilution