Gas law practice problems LE
gas
A 3.0L sample of carbon dioxide gas at 155 kPa is injected into a 5.0 L vessel. What is the new pressure of the
gas

93 kPa

Explanation:

Step 1: Given data

Step 2: Calculate the final pressure of carbon dioxide gas

If we assume carbon dioxide behaves as an ideal gas, we can calculate the final pressure of carbon dioxide gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁/V₂

P₂ = 155 kPa × 3.0 L/5.0 L = 93 kPa

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.