Find the molar mass of (NH4)2Cr207.
Answer in units of g/mol.

Answer and Explanation:

252.0649 g/mol

Nitrogen: 14.007 g/mol

Hydrogen: 1.00794 g/mol

Chromium:  51.9961 g/mol

Oxygen:  15.999 g/mol

( 2 x14.007 ) +( 8 x1.00794 ) + ( 2 x 51.9961 )+(7 x15.999 )=252.06 g/mol

346.05 g/mol

Explanation:

To find Molar Mass you basically just need to add up the atomic masses of the elements in the compound then add g/mol after.

So you would add:

(14.01+4x1.01)+(2x52.00)+(2x16.00x7)

(18.05)+(104)+(224)

=346.05 g/mol

*I hope that 0 is referring to Oxygen, if It isn't, this is not correct!*

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally