What is the empirical formula of a hypothetical compound that is 96%S and 4% H?​

Explanation:

Let the mass of the compound be 100g.

Mass of Sulfur = 96g.

=> Moles of Sulfur

= 96g / (32.07g/mol) ≈ 3

Mass of Hydrogen = 4g.

=> Moles of Hydrogen

= 4g / (1.008g/mol) ≈ 4

Mole ratio of Sulfur to Hydrogen = 3 : 4,

Empirical formula of compound = S3H4.

1.solid

2.carbon dioxide

3.helium

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