C3H8 +502 + 3CO2 + 4H2O How many grams of CO2 will be produced from 7.00 g of C3H8 and 98.0 g of O2?

Explanation:

first, you calculate the amount of O2 in moles:

98.0 ÷ 32 = 3.0625

second, the ratio if O2/C3H8 is 5 so you need to calculate O2 in moles with that:

3.0625 ÷ 5 = 0.6125

third, the amount of CO2 in moles also can be calculate by the ratio of C3H8/CO2 which is 3

0.6125 × 3 = 1.8375

then multiply CO2 in moles by its molar mass which is 44 g/mol

1.8375 × 44 = 80.85g

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.