Stoichiometry is hawd Using the following reaction:

C12H22O11 + 12 O2 → 12CO2 + 11H2O + energy

How many grams of carbon dioxide, CO2, are produced from metabolizing 448g sucrose?

691 g CO₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Organic

Stoichiometry

Step 1: Define

[RxN - Balanced] C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O + Energy

[Given] 448 g C₁₂H₂₂O₁₁ (sucrose)

[Solve] grams CO₂ (carbon dioxide)

Step 2: Identify Conversions

[RxN] 1 mol C₁₂H₂₂O₁₁ → 12 mol CO₂

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of C₁₂H₂₂O₁₁ - 12(12.01) + 22(1.01) + 11(16.00) = 342.34 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Stoich

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

691.119 g CO₂ ≈ 691 g CO₂

the increase of protons   hope this

i think its 5049.

i hope this !