If 10 grams of oxygen are combined with 1 grams of hydrogen, how much water would be formed?

36 g of water will produced.

Explanation:

Given data:

Mass of oxygen = 32 g

Mass of hydrogen = 4 g

Mass of water = ?

Solution:

First of all we will write the balance chemical equation.

 2H₂ + O₂   →  2H₂O

Moles of oxygen = mass / molar mass

Moles of oxygen = 32 g/ 32 g/mol

Moles of oxygen = 1 mol

Moles of hydrogen = mass / molar mas

Moles of hydrogen = 4 g/ 2 g/mol

Moles of hydrogen = 2 mol

Now we compare the moles of water with oxygen and hydrogen.

                 O₂       :         H₂O

                 1          :          2

                 H₂       :         H₂O

                  2        :           2

The moles of water produce by hydrogen and oxygen are same.

Mass = moles × molar mass

Mass = 2 mol × 18 g/mol = 36 g

Explanation:

the answer to your question is c.

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