What mass of sodium chloride is produced when 5.4 g of iron
chloride are used?

5.0 g

Explanation:

Step 1: Write the balanced equation

FeCl₂ + 2 Na⁺ = 2 NaCl + Fe²⁺

Step 2: Calculate the moles corresponding to 5.4 g of FeCl₂

The molar mass of FeCl₂ is 126.75 g/mol.

5.4 g × 1 mol/126.75 g = 0.043 mol

Step 3: Calculate the moles of NaCl produced from 0.043 moles of FeCl₂

The molar ratio of FeCl₂ to NaCl is 1:2. The moles of NaCl produced are 2/1 × 0.043 mol = 0.086 mol.

Step 4: Calculate the mass corresponding to 0.086 moles of NaCl

The molar mass of NaCl is 58.44 g/mol.

0.086 mol × 58.44 g/mol = 5.0 g

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g