If 4.50 moles of HNO3 are used, how many moles of copper (II) nitrate are produced?

2.25 moles of Cu(NO₃)₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Cu + 2HNO₃ —> Cu(NO₃)₂ + H₂

From the balanced equation above,

2 moles of HNO₃ reacted to produce 1 mole of Cu(NO₃)₂.

Finally, we shall determine the number of mole of Cu(NO₃)₂ produced by the reaction of 4.5 moles of HNO₃. This can be obtained as follow:

From the balanced equation above,

2 moles of HNO₃ reacted to produce 1 mole of Cu(NO₃)₂.

Therefore, 4.5 moles of HNO₃ will react to produce = 2.25 moles of Cu(NO₃)₂.

Thus, 2.25 moles of Cu(NO₃)₂ were obtained from the reaction.