A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the higher temperature to f at the lower temperature

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Where;

 is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

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because it does not have the potential to be entirely used up