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Chemistry, 25.02.2021 22:40 carlosborquez67
If you are given 68.4 grams of Mgo, how many moles is this?
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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) β c2h2 (g) + caoh2 (s) =Ξ΄hβ414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) β 5ch2chco2h (g) =Ξ΄h132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .
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If you are given 68.4 grams of Mgo, how many moles is this?...
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