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Chemistry, 26.02.2021 01:40 tori3981

Lodine dissolves in water, but its solubility in a nonpolar solvent such as CCl4 is greater. Extracting iodine (I2) from water with the nonpolar solvent CCl4. I2 is more soluble in CCl4 and,
after shaking a mixture of water and CCl4, the I2 has accumulated in the more dense CCl4 layer.
The equilibrium constant is 85.0 for the reaction:

I2(aq) —> I2(CCI4)

You place 0.0340 g of I2 in 100.0 mL of water. After shaking it with 10.0 mL of CCl4, how much I2 remains in the water layer?

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