When copper oxide is reacted with sulfuric acid, the acid is often gently heated. This is done in order to:

Copper oxide(solid) + Sulphuric Acid (aqueous)-> Copper Sulphate (aqueous)+ Water(liquid)

In equation form:

CuO +H2SO4 -> CuSO4 + H2O

The colour change you will see is black to blue as Copper oxide is usually found as a black powder. Upon the reaction with sulphuric acid it will change to a cyan blue.

If you heat the made solution of copper sulphate, the water will evaporate and you will be left with white anhydrous copper sulphate crystals.

The answer is 1.82 j/g°c