2Na + Cl₂ --> 2NaCl, if you start with 0.50 mol of sodium and you ultimately produce 0.43 mol in lab, what is your percent yield?

86% is the percent yield of the reaction

Explanation:

Percent yield is defined as 100 times the ratio of actual yield / theoretical yield.

Based on the reaction:

2Na + Cl₂ → 2NaCl

The theoretical yield is 0.50 moles because 0.50 mol of Na are added in the beginning. As 0.43 moles are produced, actual yield is 0.43 mol. And percent yield is:

0.43mol / 0.50mol * 100 =

its first and third is your answer i did the qustion the fourth isnt right

where are the choice options?