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Silicon dioxide (quartz) is usually quite unreactive but reacts readily with
hydrogen fluoride according to the equation
SiO2(s) + 4HF(g) - SiF4(g) + 2H2O(1)
If 3.0 mol of HF are exposed to 5.5 mol of SiO2, which is the limiting reactant?
How many moles of excess reagent remain?
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